A. Brain's Photos
time limit per test 2 seconds
memory limit per test 256 megabytes
input standard input
output standard output
Small,
but very brave, mouse Brain was not accepted to summer school of young
villains. He was upset and decided to postpone his plans of taking over the
world, but to become a photographer instead.
As you
may know, the coolest photos are on the film (because you can specify the
hashtag #film for such).
Brain
took a lot of colourful pictures on colored and black-and-white film. Then he
developed and translated it into a digital form. But now, color and
black-and-white photos are in one folder, and to sort them, one needs to spend
more than one hour!
As soon
as Brain is a photographer not programmer now, he asks you to help him
determine for a single photo whether it is colored or
black-and-white.
Photo can
be represented as a matrix sized n × m, and each element of
the matrix stores a symbol indicating corresponding pixel color. There are only 6 colors:
·
'C' (cyan)
·
'M' (magenta)
·
'Y' (yellow)
·
'W' (white)
·
'G' (grey)
·
'B' (black)
The photo
is considered black-and-white if it has only white, black and grey pixels in
it. If there are any of cyan, magenta or yellow pixels in the photo then it is
considered colored.
Input
The first
line of the input contains two integers n and m (1 ≤ n, m ≤ 100) —
the number of photo pixel matrix rows and columns respectively.
Then n lines
describing matrix rows follow. Each of them contains m space-separated
characters describing colors of pixels in a row. Each character in the line is
one of the 'C', 'M', 'Y', 'W', 'G' or 'B'.
Output
Print the
"#Black&White" (without quotes), if the photo is black-and-white
and "#Color" (without quotes), if it is colored, in the only line.
Examples
input
2 2
C M
Y Y
output
#Color
input
3 2
W W
W W
B B
output
#Black&White
input
1 1
W
output
#Black&White
Problem link : https://codeforces.com/problemset/problem/707/A
Solution
:
- [tab]
- C++
#include<bits/stdc++.h> using namespace std; int main() { int n,m,i,j; cin>>n>>m; char s[n][m]; for(i=0;i<n;i++) { for(j=0;j<m;j++) { cin>>s[i][j]; } } for(i=0;i<n;i++) { for(j=0;j<m;j++) { if(s[i][j]=='M'||s[i][j]=='Y'||s[i][j]=='C') { cout<<"#Color"<<endl; return 0; } } } cout<<"#Black&White"<<endl; return 0; }