URI-1046 Solve

Game Time

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read the start time and end time of a game, in hours. Then calculate the duration of the game, knowing that the game can begin in a day and finish in another day, with a maximum duration of 24 hours. The message must be printed in portuguese “O JOGO DUROU X HORA(S)” that means “THE GAME LASTED X HOUR(S)”

Input

Two integer numbers representing the start and end time of a game.

Output

Print the duration of the game as in the sample output.

Input Sample	Output Sample
16 2	O JOGO DUROU 10 HORA(S)

0 0	O JOGO DUROU 24 HORA(S)

2 16	O JOGO DUROU 14 HORA(S)

Problem link [URI 1046##link##]

Solution

• [tab]
• C

• #include <stdio.h>
  
  int main()
  
  {
  
      int strtTm, endTm, durationTm;
  
      scanf("%d %d", &strtTm, &endTm);
  
      durationTm = endTm - strtTm;
  
      if (durationTm < 0)
  
      {
  
          durationTm = 24 + (endTm - strtTm);
  
      }
  
      if (strtTm == endTm)
  
      {
  
          printf("O JOGO DUROU 24 HORA(S)\n");
  
      }
  
      else printf("O JOGO DUROU %d HORA(S)\n", durationTm);
  
  
  
      return 0;
  
  }

• C++

• #include <iostream>
  
  using namespace std;
  
  int main()
  {
   int i, f;
   int ctr = 0;
  
   cin >> i >> f;
  
   if(i == f){
    cout << "O JOGO DUROU 24 HORA(S)" << endl;
    return 0;
   }
  
   while(i != f)
   {
    ctr++;
    i++;
    if(i == 25)
     i = 1;
   }
  
   cout << "O JOGO DUROU " << ctr <<  " HORA(S)" << endl;
  
   return 0;
  }