URI-1041 Solve

Coordinates of a Point

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Write an algorithm that reads two floating values (x and y), which should represent the coordinates of a point in a plane. Next, determine which quadrant the point belongs, or if you are over one of the Cartesian axes or the origin (x = y = 0).

If the point is at the origin, write the message "Origem".

If the point is over X axis write "Eixo X", else if the point is over Y axis write "Eixo Y".

Input

The input contains the coordinates of a point.

Output

The output should display the quadrant in which the point is.

Input Sample	Output Sample
4.5 -2.2	Q4

0.1 0.1

Q1

0.0 0.0

Origem

Problem Link: [URI-1041##link##]

Solution

• [tab]
• C

• #include<stdio.h>
  int main()
  {
      float a,b;
      while(scanf("%f %f",&a,&b)==2)
      {
  
          if(a==0 && b==0)
              printf("Origem\n");
  
          else if(b==0)
              printf("Eixo X\n");
  
          else if(a==0)
              printf("Eixo Y\n");
  
          else if(a>0 && b>0)
              printf("Q1\n");
  
          else if(a<0 && b>0)
              printf("Q2\n");
  
          else if(a<0 && b<0)
              printf("Q3\n");
          else
              printf("Q4\n");
  
      }
      return 0;
  }

• C++

• #include <cstdio>
  
  int main()
  {
   float x;
   float y;
  
   scanf("%f", &x);
   scanf("%f", &y);
  
   if(x == 0 && y == 0){
    printf("Origem\n");
   }else if(x == 0){
    printf("Eixo Y\n");
   }else if(y == 0){
    printf("Eixo X\n");
   }else if(x > 0 && y > 0){
    printf("Q1\n");
   }else if(x > 0 && y < 0){
    printf("Q4\n");
   }else if(x < 0 && y > 0){
    printf("Q2\n");
   }else{
    printf("Q3\n");
   }
  
   return 0;
  
  }