URI-1043 Solve

Triangle

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read three point floating values (A, B and C) and verify if is possible to make a triangle with them. If it is possible, calculate the perimeter of the triangle and print the message:

Perimetro = XX.X

If it is not possible, calculate the area of the trapezium which basis A and B and C as height, and print the message:

Area = XX.X

Input

The input file has tree floating point numbers.

Output

Print the result with one digit after the decimal point.

Input Sample	Output Sample
6.0 4.0 2.0	Area = 10.0

6.0 4.0 2.1

Perimetro = 12.1

Problem link: [URI-1043##link##]

Solution

• [tab]
• C

• #include<stdio.h>
  int main()
  {
      float A, B, C, areaTraphisium, perimeterTriangle ;
  
      scanf("%f %f %f", &A, &B, &C);
  
      if ((A < (float)(B+C)) && (B < (float)(A+C)) && (C < (float)(B+A)))
      {
          perimeterTriangle = A + B + C;
          printf("Perimetro = %.1f\n",perimeterTriangle);
  
  
      }
      else
      {
          areaTraphisium = ((A + B) * C) / 2;
          printf("Area = %.1f\n",areaTraphisium);
      }
      return 0;
  }

• C++

• #include <iostream>
  #include <iomanip>
  
  using namespace std;
  
  int main()
  {
   float a, b, c;
   bool ver = false;
  
   cin >> a >> b >> c;
  
   float mod = b - c;
   if(mod < 0)
    mod = -mod;
  
   if(mod < a && a < (b + c)){
    cout << "Perimetro = " << fixed << setprecision(1) << (a + b + c) << endl; 
   }else{
    cout << "Area = " << fixed << setprecision(1) << ((a + b) * c) / 2 << endl; 
   }
  
   return 0;
  }