URI-1020 Solve

Age in Days

Adapted by Neilor Tonin, URI  Brazil

Timelimit: 1

Read an integer value corresponding to a person's age (in days) and print it in years, months and days, followed by its respective message “ano(s)”, “mes(es)”, “dia(s)”.

Note: only to facilitate the calculation, consider the whole year with 365 days and 30 days every month. In the cases of test there will never be a situation that allows 12 months and some days, like 360, 363 or 364. This is just an exercise for the purpose of testing simple mathematical reasoning.

Input

The input file contains 1 integer value.

Output

Print the output, like the following example.

Input Sample	Output Sample
400	1 ano(s) 1 mes(es) 5 dia(s)

800	2 ano(s) 2 mes(es) 10 dia(s)

30	0 ano(s) 1 mes(es) 0 dia(s)

Problem link: https://www.urionlinejudge.com.br/judge/en/problems/view/1020

Solution:

• [tab]
• C

• #include<stdio.h>
  
   int main(){
  
      int y, m, d, n;
  
      scanf("%d", &n);
      y = n / 365;
      m = n % 365 / 30;
      d = n % 365 % 30;
      printf("%d ano(s)\n%d mes(es)\n%d dia(s)\n", y, m, d);
  
      return 0;
  
   }

• C++

• #include <iostream>
  
  using namespace std;
  
  int main()
  {
   int n;
   
   cin >> n;
   
   int a = n / 365;
   int rA = n % 365;
   int rM = rA % 30;
   int m = rA / 30;
   int d = rM % 30;
   
   cout << a << " ano(s)" << endl << m << " mes(es)" << endl << d << " dia(s)" << endl;
   
   return 0;
  }